JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

  • question_answer
    An ideal refrigerator has a freezer at a temperature of \[-13{}^\circ C.\] The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) will be

    A) 325°C

    B) 325K

    C) 39°C    

    D) 320°C

    Correct Answer: C

    Solution :

    [c]Coefficient of performance
                Þ \[5{{T}_{1}}-1300=260\]Þ \[5{{T}_{1}}=1560\]
                Þ \[{{T}_{1}}=312K\to 39{}^\circ C\]

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