JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

An ideal gas heat engine operates in a Carnot's cycle between \[{{227}^{o}}C\] and \[{{127}^{o}}C\]. It absorbs 6 × 104 J at high temperature. The amount of heat converted into work is ....

A) \[4.8\times {{10}^{4}}\,J\]

B) \[3.5\times {{10}^{4}}\,J\]

C) \[1.6\times {{10}^{4}}\,J\]

D) \[1.2\times {{10}^{4}}\,J\]

Correct Answer: D

Solution :

[d]\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{400}{500}=\frac{1}{5}\] \[\because \ \eta =\frac{W}{Q}\] Þ \[\frac{1}{5}=\frac{W}{Q}\]

Þ \[W=\frac{Q}{5}=\frac{6}{5}\times {{10}^{4}}=1.2\times {{10}^{4}}\,J\]