JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

  • question_answer
    An ideal gas heat engine operates in a Carnot's cycle between \[{{227}^{o}}C\] and \[{{127}^{o}}C\]. It absorbs 6 × 104 J at high temperature. The amount of heat converted into work is ....

    A) \[4.8\times {{10}^{4}}\,J\]

    B) \[3.5\times {{10}^{4}}\,J\]

    C) \[1.6\times {{10}^{4}}\,J\]

    D) \[1.2\times {{10}^{4}}\,J\]

    Correct Answer: D

    Solution :

    [d]\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{400}{500}=\frac{1}{5}\]     \[\because \ \eta =\frac{W}{Q}\] Þ \[\frac{1}{5}=\frac{W}{Q}\]
    Þ \[W=\frac{Q}{5}=\frac{6}{5}\times {{10}^{4}}=1.2\times {{10}^{4}}\,J\]

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