A) 1000 K
B) 960 K
C) 846 K
D) 754 K
Correct Answer: B
Solution :
[b] In first case, \[({{\eta }_{1}})=1-\frac{500}{800}=\frac{3}{8}\] |
and in second case, \[({{\eta }_{2}})=1-\frac{600}{x}\] |
Since \[{{\eta }_{1}}={{\eta }_{2}},\] therefore \[\frac{3}{8}=1-\frac{600}{x}\] |
or \[\frac{600}{x}=1-\frac{3}{8}=\frac{5}{8}\]or\[x=\frac{600\times 8}{5}=960K\] |
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