A) \[10.2eV\]
B) \[12.09eV\]
C) \[1.9eV\]
D) \[0.65eV\]
Correct Answer: C
Solution :
[c] \[\Delta E={{E}_{3}}-{{E}_{2}}=13.6\,\left[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(3)}^{2}}} \right]=1.9\,eV\]
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