JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry / रसायन की कुछ मूलभूत अवधारणाएँ Question Bank Topic Test - Some Basic Concepts of Chemistry (8-5-21)

  • question_answer
    On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of metal. If the vapour density of metal is 32, the simplest formula of the oxide would be

    A) \[MO\]

    B) \[{{M}_{2}}{{O}_{3}}\]

    C) \[{{M}_{2}}O\]0

    D) \[{{M}_{2}}{{O}_{5}}\]

    Correct Answer: C

    Solution :

    [c] As  we know that
                Equivalent weight \[=\frac{\text{weight of metal}}{\text{weight of oxygen}}\times 8\]
                                            \[=\frac{32}{0.4}\times 8=64\]
                Vapour density \[=\frac{\text{mol}\text{. wt}}{\text{2}}\]
                Mol. wt \[=2\times V.D=2\times 32=64\]
                As we know that \[n=\frac{\text{mol}\text{.}\,\text{wt}}{\text{eq}\text{. wt}}=\frac{64}{64}=1\]
                            Suppose, the formula of metal oxide be \[{{M}_{2}}{{O}_{n}}\]. Hence the formula of metal oxide \[={{M}_{2}}O\].


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