A) 21
B) 54
C) 27.06
D) 2.086
Correct Answer: C
Solution :
| [c] Let wt. of metal oxide = 100gm |
| wt. of metal = 53gm |
| wt. of oxygen = 47gm |
| Equivalent weight of oxygen\[=\frac{\text{wt}\text{. of metal}}{\text{wt}\text{. of oxygen}}\times 8\] |
| \[=\frac{53}{47}\times 8=9.02\] |
| Valency \[=\frac{2\times V.D}{E+35.5}=\frac{2\times 66}{9+35.5}=\frac{132}{44.5}=2.96\approx 3\] |
| \[\therefore \] Atomic weight \[=\text{Equivalent weight}\times \text{Valency}\] |
| \[=9.02\times 3=27.06\] |
You need to login to perform this action.
You will be redirected in
3 sec
