A) 47.2 g
B) 5g
C) 106.2g
D) None of these
Correct Answer: B
Solution :
| [b] \[{{P}_{s}}=\left( \frac{80}{100} \right){{P}^{o}},w=?\] |
| \[{{M}_{solute}}=40,\,w=114g,\,{{M}_{solvent}}=114\] |
| \[\frac{P_{{}}^{O}-{{P}_{s}}}{{{P}_{s}}}=\frac{w\times {{M}_{solvent}}}{{{M}_{solute}}\times W}\] |
| or \[\frac{P_{{}}^{O}-\left( 80/100 \right){{P}^{O}}}{\left( 80/100 \right){{P}^{O}}}=\frac{w\times 114}{40\times 57}\] |
| \[\therefore \] \[w=5g\] |
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