A) \[[Fe{{({{H}_{2}}O)}_{6}}]C{{l}_{3}}\]
B) \[[Fe{{({{H}_{2}}O)}_{5}}Cl]C{{l}_{2}}.{{H}_{2}}O\]
C) \[[Fe{{({{H}_{2}}O)}_{4}}C{{l}_{2}}]Cl.\,2{{H}_{2}}O\]
D) \[[Fe{{({{H}_{2}}O)}_{3}}C{{l}_{3}}].\,3{{H}_{2}}O\]
Correct Answer: D
Solution :
| [d] In 4 option their is no ionization |
| \[\Delta {{T}_{f}}\propto {{i}^{o}}\] |
| \[F.P=0-\Delta {{T}_{f}}\] |
| Hence greater the value of \[\Delta {{T}_{f}},\] smaller the F.P. hence maximum freezing points is of '4' option. |
You need to login to perform this action.
You will be redirected in
3 sec
