JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Topic Test - Solid State

The composition of sample of wustite is \[F{{e}_{0.93}}{{O}_{1.00}}\]. What percentage of the iron is present in the form of Fe (III)?

A) 14%

B) 15.05%

C) 17%

D) 29%

Correct Answer: B

Solution :

[b] \[F{{e}_{0.93}}{{O}_{1.00}}\]

Oxidation number of \[F{{e}_{0.93}}\]

= + 2 (0.93 mol possess net + 2 charge)

Suppose x mol + 2 charge.

then 0.93 - x posses + 3 charge

Hence, \[x\times 2+3(0.93-x)=+2\]

\[x=0.79\,F{{e}^{2+}};\,F{{e}^{3+}}=0.14\]

\[F{{e}^{3+}}%=\frac{0.14}{0.93}\times 100=15.05%\]