A) 1
B) 3
C) 2
D) 4
Correct Answer: A
Solution :
[a] \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{X}^{n+}}\xrightarrow[{}]{{}}{{X}^{5+}}O_{3}^{-}+C{{r}^{3+}}\] \[6\times {{10}^{-3}}\times 6=(5-n)\times 9\times {{10}^{-3}}\] Implies \[n=1\] In \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] oxidation state of \[Cr=6\] X have change in oxidation number \[=(5-n)\].
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