A) \[{{d}_{{{x}^{2}}-{{y}^{2}}}}\]atomic orbital - One nodal plane
B) \[{{p}_{y}}\] atomic orbital - Two nodal planes
C) \[{{\sigma }_{{{p}_{x}}}}\] molecular orbital - \[\Psi \](gerade)
D) \[\pi _{{{p}_{y}}}^{*}\] molecularorbital - \[\Psi \](ungerade)
Correct Answer: C
Solution :
[c]\[\sigma \]bonding molecular orbital is gerade due to having center of symmetry.
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