A) 13.2 E
B) 7.2 E
C) 5.6 E
D) 3.2 E
Correct Answer: B
Solution :
| (b) Energy \[=0.0258\ amu\] (K = constant) |
| n1 = 2 and n2 = 3, so \[E=K\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]=K\left[ \frac{5}{36} \right]\] |
| For removing an electron n1 = 1 to \[{{n}_{2}}=\infty \] |
| Energy \[{{E}_{1}}=K[1]=\frac{36}{5}E=7.2\ E\] |
| \[\therefore \]Ionization energy = 7.2 E |
You need to login to perform this action.
You will be redirected in
3 sec
