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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Time Period and Frequency

  • question_answer
    The motion of a particle executing S.H.M. is given by \[x=0.01\sin 100\pi (t+.05)\], where x is in metres and time is in seconds. The time period is               [CPMT 1990]

    A)            0.01 sec                                  

    B)            0.02 sec

    C)            0.1 sec                                     

    D)            0.2 sec

    Correct Answer: B

    Solution :

               \[\omega =\frac{2\pi }{T}=100\pi \Rightarrow T=0.02\ \sec \]


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