A) 3 Hz
B) 2 Hz
C) 4 Hz
D) 1 Hz
Correct Answer: D
Solution :
\[{{v}_{\max }}=a\omega =a\times 2\pi n\] Þ \[n=\frac{{{v}_{\max }}}{2\pi a}=\frac{31.4}{2\times 3.14\times 5}=1\,Hz\]
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