A) 1 cm
B) \[\sqrt{2}\]cm
C) 2 cm
D) 2.5 cm
Correct Answer: B
Solution :
Given, \[v=\pi \,cm/\sec ,\] \[x=1\,cm\] and \[\omega =\pi {{s}^{-1}}\] using \[v=\omega \sqrt{{{a}^{2}}-{{x}^{2}}}\]Þ \[\pi =\pi \sqrt{{{a}^{2}}-1}\] \[\Rightarrow 1={{A}^{2}}-1\]\[\Rightarrow A=\sqrt{2}\,cm.\]You need to login to perform this action.
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