JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Thermometry

  • question_answer
    If temperature of an object is 140°F, then its temperature in centigrade is                                            [RPMT 1999]

    A)            105°C                                       

    B)            32°C

    C)            140°C                                       

    D)            60°C

    Correct Answer: D

    Solution :

               \[\frac{C}{5}=\frac{F-32}{9}\] Þ \[\frac{C}{5}=\frac{140-32}{9}\] Þ \[C=60{}^\circ C\]


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