A) ? 273°F
B) ? 32°F
C) ? 460°F
D) ? 132°F
Correct Answer: C
Solution :
\[\frac{F-32}{9}=\frac{K-273}{5}\] Þ \[\frac{F-32}{9}=\frac{0-273}{5}\] Þ \[F=-459.4{}^\circ F\approx -460{}^\circ F\]
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