A) 25°C
B) 40°C
C) 15°C
D) 12.5°C
Correct Answer: A
Solution :
\[t=\frac{({{P}_{t}}-{{P}_{0}})}{({{P}_{100}}-{{P}_{0}})}\times 100{}^\circ C=\frac{(60-50)}{(90-50)}\times 100=25{}^\circ C\]
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