A) 215°F
B) ? 297°F
C) 329°F
D) 361°F
Correct Answer: B
Solution :
\[\frac{C}{5}=\frac{F-32}{9}\] Þ \[\frac{-183}{5}=\frac{F-32}{9}\] Þ \[F=-297{}^\circ F\]
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