A) \[10\,m\]
B) \[20\,m\]
C) \[5\,m\]
D) \[25\,m\]
Correct Answer: A
Solution :
In \[\Delta PRQ,\] \[P{{R}^{2}}=P{{Q}^{2}}+Q{{R}^{2}}\] (By Pythagoras theorem) \[{{(26)}^{2}}={{(24)}^{2}}+Q{{R}^{2}}\] or \[Q{{R}^{2}}=676-576=100\] \[\Rightarrow \] \[QR=\sqrt{100}\Rightarrow QR=10\] \[\therefore \] The distance of the foot of the ladder from the wall is 10 m.You need to login to perform this action.
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