A) \[1.2\times {{10}^{23}}\]
B) \[6\times {{10}^{22}}\]
C) \[6\times {{10}^{23}}\]
D) \[12\times {{10}^{23}}\]
Correct Answer: A
Solution :
44g of CO2 has \[2\times 6\times {{10}^{23}}\]atoms of oxygen 4.4g of CO2 has =\[\frac{12\times {{10}^{23}}}{44}\times 4.4\] \[=1.2\times {{10}^{23}}\] atoms.
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