A) \[{{a}^{2}}={{c}^{2}}(2m+1)\]
B) \[{{a}^{2}}={{c}^{2}}(2+{{m}^{2}})\]
C) \[{{c}^{2}}={{a}^{2}}(2+{{m}^{2}})\]
D) \[{{c}^{2}}={{a}^{2}}(2m+1)\]
Correct Answer: C
Solution :
Equation of circles \[[{{x}^{2}}+(y-a)(y+a)]+\lambda x=0\Rightarrow {{x}^{2}}+{{y}^{2}}+\lambda x-{{a}^{2}}=0\]You need to login to perform this action.
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