A) \[c=\sqrt{2}\]
B) \[c=-\sqrt{2}\]
C) \[c=\pm \sqrt{2}\]
D) None of these
Correct Answer: C
Solution :
\[y=x+c\] intersects at two coincident points, i.e. it is a tangent, therefore \[{{c}^{2}}=1(1+1)\Rightarrow c=\pm \sqrt{2}\].
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