A) \[{{x}^{2}}+{{y}^{2}}=4{{a}^{2}}\]
B) \[{{x}^{2}}+{{y}^{2}}=\sqrt{2}{{a}^{2}}\]
C) \[{{x}^{2}}+{{y}^{2}}-2{{a}^{2}}=0\]
D) None of these
Correct Answer: C
Solution :
Director circle has its radius \[\sqrt{2}\] times that of radius of the given circle. Hence equation is \[{{x}^{2}}+{{y}^{2}}=2{{a}^{2}}\].
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