A) - 3
B) 1/2
C) 0
D) 2
Correct Answer: A
Solution :
For the equation to be inconsistent \[D=0\] \[\therefore \]\[D=\left| \,\begin{matrix} 1 & 2 & -3 \\ 0 & 0 & k+3 \\ 2k+1 & 0 & 1 \\ \end{matrix}\, \right|=0\Rightarrow k=-3\] and \[{{D}_{1}}=\left| \,\begin{matrix} 1 & 2 & -3 \\ 3 & 0 & 0 \\ 0 & 0 & 1 \\ \end{matrix}\, \right|\ne 0\] So that system is inconsistent for\[k=-3\].
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