A) \[(1,0)\]
B) \[(-1,0)\]
C) \[(1,\text{ }1)\]
D) None of these
Correct Answer: B
Solution :
Let A (3, - 4) and C(- 6, 5) be the ends of diagonal of parallelogram ABCD. Let B (- 2, 1) and D be (x, y). Then mid-points of diagonals AC and BD coincide. So \[\frac{x-2}{2}=\frac{-6+3}{2}\] and \[\frac{y+1}{2}=\frac{5-4}{2}\,\,\Rightarrow \,\,x=-1,\,\,y=0\] \[\therefore \] Coordinates of D are (-1, 0).You need to login to perform this action.
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