A) 1
B) -1
C) \[\sqrt{3}\]
D) \[-\sqrt{3}\]
Correct Answer: C
Solution :
\[{{l}^{2}}={{2}^{2}}+{{2}^{2}}=8={{(\sqrt{3}+1)}^{2}}+{{(k-1)}^{2}}\,\,\Rightarrow \,\,k=\sqrt{3}\].You need to login to perform this action.
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