A) \[\frac{\sqrt{23}}{6}\]
B) \[\frac{23}{6}\]
C) \[\frac{2}{3}\]
D) \[\frac{3}{2}\]
Correct Answer: A
Solution :
If \[\left( \frac{1}{2},\,\frac{1}{3},\,n \right)\] are the d.c?s of line then, \[{{\left( \frac{1}{2} \right)}^{2}}+{{\left( \frac{1}{3} \right)}^{2}}+{{n}^{2}}=1\] Þ \[{{n}^{2}}=\frac{23}{36}\] Þ \[n=\frac{\sqrt{23}}{6}\].
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