A) 3, 4, 12
B) ? 3, ? 4, ? 12
C) \[\frac{3}{13},\frac{4}{13},\frac{12}{13}\]
D) \[\frac{3}{\sqrt{13}},\frac{4}{\sqrt{13}},\frac{12}{\sqrt{13}}\]
Correct Answer: C
Solution :
Direction ratio of normal to the plane \[3x+4y+12z=52\] is 3, 4, 12. \[\therefore \]D.c's are\[\left( \frac{3}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{12}^{2}}}},\,\frac{4}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{12}^{2}}}},\frac{12}{\sqrt{{{3}^{2}}+{{4}^{2}}+{{12}^{2}}}} \right)\] \[=\left( \frac{3}{13},\frac{4}{13},\frac{12}{13} \right)\].
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