A) \[\left( \frac{1}{3},\frac{2}{3},\,0 \right)\]
B) \[\left( -1,\frac{2}{3},\,1 \right)\]
C) \[\left( -\frac{1}{2},\,\text{ }1,\,-\frac{1}{2} \right)\]
D) \[\left( -\frac{1}{\sqrt{6}},\frac{2}{\sqrt{6}},-\frac{1}{\sqrt{6}} \right)\]
Correct Answer: D
Solution :
Change the given equation in standard form, we get, \[\,\,\frac{x+\frac{1}{3}}{-1}=\frac{y+\frac{2}{3}}{2}=\frac{z}{-1}\] So direction cosine are,\[\left( \frac{-1}{\sqrt{6}},\,\frac{2}{\sqrt{6}},\frac{-1}{\sqrt{6}} \right)\].
You need to login to perform this action.
You will be redirected in
3 sec
