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JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    In order to float a ring of area 0.04 m2 in a liquid of surface tension 75 N/m, the required surface energy will be [RPMT 2003]

    A) 3 J      

    B)             6.5 J

    C)             1.5 J   

    D)             4 J

    Correct Answer: A

    Solution :

                    \[E=T\times \Delta A=75\times 0.04=3\,J\]


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