A) \[192\pi \times {{10}^{-4}}J\]
B) \[280\pi \times {{10}^{-4}}J\]
C) \[200\pi \times {{10}^{-3}}J\]
D) None of these
Correct Answer: A
Solution :
\[W=8\pi {{r}^{2}}\times T=8\pi \times {{(0.2)}^{2}}\times 0.06=192\pi \times {{10}^{-4}}\,J\]
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