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JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    Two small drops of mercury, each of radius R, coalesce to form a single large drop. The ratio of the total surface energies before and after the change is [AIIMS 2003; DCE 2003]

    A)             \[1:{{2}^{1/3}}\]

    B)                      \[{{2}^{1/3}}:1\]

    C)             2 : 1    

    D)             1 : 2

    Correct Answer: B

    Solution :

                    The ratio of the total surface energies before and after the change \[={{n}^{1/3}}:1={{2}^{1/3}}:1\]


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