A) \[7.22\times {{10}^{-6}}\,Joule\]
B) \[1.44\times {{10}^{-5}}\,Joule\]
C) \[2.88\times {{10}^{-5}}\,Joule\]
D) \[5.76\times {{10}^{-5}}\,Joule\]
Correct Answer: B
Solution :
Increment in area of soap film = \[{{A}_{2}}-{{A}_{1}}\] \[=2\times [(10\times 0.6)-(10\times 0.5)]\times {{10}^{-4}}=2\times {{10}^{-4}}{{m}^{2}}\] Work done = \[T\times \Delta A\] \[=7.2\times {{10}^{-2}}\times 2\times {{10}^{-4}}=1.44\times {{10}^{-5}}J\]
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