A) 0.057
B) 5.7
C) \[5.7\times {{10}^{-4}}\]
D) \[5.7\times {{10}^{-6}}\]
Correct Answer: A
Solution :
\[W=T\Delta A=4\pi {{R}^{2}}T({{n}^{1/3}}-1)\] \[=4\times 3.14\times {{({{10}^{-2}})}^{2}}\times 460\times {{10}^{-3}}\times [{{({{10}^{6}})}^{1/3}}-1]\]\[=0.057\]
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