JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    If work done in increasing the size of a soap film from \[10\ cm\times 6\ cm\] to \[10\ cm\times 11\ cm\] is \[2\times {{10}^{-4}}J,\] then the surface tension is                                       [AIIMS 2000]

    A)             \[2\times {{10}^{-2}}N{{m}^{-1}}\]

    B)                      \[2\times {{10}^{-4}}N{{m}^{-1}}\]

    C)             \[2\times {{10}^{-6}}N{{m}^{-1}}\]       

    D)             \[2\times {{10}^{-8}}N{{m}^{-1}}\]

    Correct Answer: A

    Solution :

                    \[T=\frac{W}{\Delta A}=\frac{2\times {{10}^{-4}}}{2\times (50\times {{10}^{-4}})}=2\times {{10}^{-2}}\ N/m\]


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