question_answer

If s be the surface tension, the work done in breaking a big drop of radius R in n drops of equal radius is [Bihar CEET 1995]

A)             \[R{{n}^{2/3}}\sigma \]

B)                      \[({{n}^{2/3}}-1)R\sigma \]

C)             \[({{n}^{1/3}}-1)R\sigma \]

D)             \[4\pi {{R}^{2}}({{n}^{1/3}}-1)\sigma \]

E)             \[\frac{1}{{{n}^{1/3}}-1}\sigma R\]