A) \[1.5\times {{10}^{-2}}N/m\]
B) \[3.0\times {{10}^{-2}}N/m\]
C) \[6.0\times {{10}^{-2}}N/m\]
D) \[11.0\times {{10}^{-2}}N/m\]
Correct Answer: B
Solution :
\[W=T\times \Delta A\] \ \[T=\frac{W}{\Delta A}\] \[T=\frac{3\times {{10}^{-4}}}{2\times (110-60)\times {{10}^{-4}}}\](Soap film has two surfaces) =\[3\times {{10}^{-2}}N/m\]
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