A) \[\pi {{D}^{2}}\sigma \]
B) \[2\pi {{D}^{2}}\sigma \]
C) \[3\pi {{D}^{2}}\sigma \]
D) \[4\pi {{D}^{2}}\sigma \]
Correct Answer: B
Solution :
Work done = \[4\pi {{R}^{2}}T({{n}^{1/3}}-1)\]\[=4\pi {{\left( \frac{D}{2} \right)}^{2}}\sigma ({{n}^{1/3}}-1)\] \[=\pi {{D}^{2}}\sigma ({{27}^{1/3}}-1)\]\[=2\pi {{D}^{2}}\sigma \]
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