JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is \[\frac{3}{100}N/m\])  [MP PMT 1995; MH CET 2002]

    A)             \[75.36\times {{10}^{-4}}joule\]     

    B)             \[37.68\times {{10}^{-4}}joule\]

    C)             \[150.72\times {{10}^{-4}}joule\]

    D)                      \[75.36joule\]

    Correct Answer: A

    Solution :

                    \[W=8\pi {{R}^{2}}T=8\times 3.14\times (10\times {{10}^{-2}})\times \frac{3}{100}\]             \[=7.536\times {{10}^{-3}}J\]


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