A) \[6\times {{10}^{-4}}\,J\]
B) \[3\times {{10}^{-4}}\,J\]
C) \[6\times {{10}^{-3}}\,J\]
D) \[3\times {{10}^{-4}}\,J\]
Correct Answer: A
Solution :
\[E=T\times \Delta A=3\times {{10}^{-2}}\times 2(100\times {{10}^{-4}})=6\times {{10}^{-4}}J\]
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