JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    The surface tension of liquid is 0.5 N/m. If a film is held on a ring of area 0.02 m2, its surface energy is           [CPMT 1977]

    A)             \[5\text{ }\times \text{ }{{10}^{-2}}joule\] 

    B)              \[2.0\text{ }\times \text{ }{{10}^{-2}}joule\]

    C)             \[4\text{ }\times \text{ }{{10}^{-4}}joule\] 

    D)              \[0.8\text{ }\times \text{ }{{10}^{-1}}joule\]

    Correct Answer: B

    Solution :

                    Surface energy = \[T\times \Delta A=0.5\times 2\times (0.02)\]= \[2\times {{10}^{-2}}J\]


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