A) \[7.6\times {{10}^{-6}}\pi \]joule
B) \[15.2\times {{10}^{-6}}\pi \]joule
C) \[1.9\times {{10}^{-6}}\pi \]joule
D) \[1\times {{10}^{-4}}\pi \]joule
Correct Answer: B
Solution :
\[W=8\pi {{R}^{2}}T=8\pi \times {{(1\times {{10}^{-2}})}^{2}}\times 1.9\times {{10}^{-2}}\]=\[15.2\times {{10}^{-6}}\pi J\]
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