A) \[4.4\times {{10}^{-3}}J\]
B) \[2.2\times {{10}^{-4}}J\]
C) \[8.8\times {{10}^{-4}}J\]
D) \[{{10}^{4}}J\]
Correct Answer: A
Solution :
\[E=4\pi {{R}^{2}}T({{n}^{1/3}}-1)\] \[=4\times 3.14\times {{10}^{-4}}\times 35\times {{10}^{-1}}({{10}^{6/3}}-1)\]\[=4.4\times {{10}^{-3}}J\]
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