A) \[4\pi \times {{10}^{-6}}J\]
B) \[8\pi \times {{10}^{-6}}J\]
C) \[12\pi \times {{10}^{-6}}J\]
D) \[16\pi \times {{10}^{-6}}J\]
Correct Answer: D
Solution :
\[W=8\pi {{R}^{2}}T=8\times \pi \times {{({{10}^{-2}})}^{2}}\times 2\times {{10}^{-2}}\]\[=16\pi \times {{10}^{-6}}J\]
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