JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Energy

  • question_answer
    The radius of a soap bubble is increased from \[\frac{1}{\sqrt{\pi }}\]cm to \[\frac{2}{\sqrt{\pi }}\]cm. If the surface tension of water is 30 dynes per cm, then the work done will be                                  [MP PMT 1986]

    A) 180 ergs

    B)                       360 ergs

    C)             720 ergs          

    D)              960 ergs

    Correct Answer: C

    Solution :

                    \[W=8\pi T(r_{2}^{2}-r_{1}^{2})\]\[=8\pi T\left[ {{\left( \frac{2}{\sqrt{\pi }} \right)}^{2}}-{{\left( \frac{1}{\sqrt{\pi }} \right)}^{2}} \right]\] W = \[8\times \pi \times 30\times \frac{3}{\pi }\]\[=720\ erg\]


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