A) \[4\pi T(n{{r}^{2}}-{{R}^{2}})\]
B) \[\frac{4}{3}\pi ({{r}^{3}}n-{{R}^{2}})\]
C) \[4\pi T({{R}^{2}}-n{{r}^{2}})\]
D) \[4\pi T(n{{r}^{2}}+{{R}^{2}})\]
Correct Answer: A
Solution :
Energy needed = Increment in surface energy = (surface energy of n small drops) ? (surface energy of one big drop) \[=n4\pi {{r}^{2}}T-4\pi {{R}^{2}}T=4\pi T(n{{r}^{2}}-{{R}^{2}})\]
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