A) \[48150\,c{{m}^{3}}\]
B) \[48510\,c{{m}^{3}}\]
C) \[48105\,c{{m}^{3}}\]
D) \[48205\,c{{m}^{3}}\]
Correct Answer: B
Solution :
Volume of frustum/bucket \[=\frac{1}{3}\pi h(r_{1}^{2}+r_{2}^{2}+{{r}_{1}}{{r}_{2}})\] \[=\frac{1}{3}\pi \times 45[{{(28)}^{2}}+{{(7)}^{2}}+(28\times 7)]=48510\,c{{m}^{3}}\]You need to login to perform this action.
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