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9th Class Mathematics Surface Areas and Volumes Question Bank Surface Area and Volume

  • question_answer
    The Level of water of a swimming pool is rectangular of which length is 32 metres and width is 9.5 metres and the depth of water at one end is \[1\frac{1}{2}\]metres which Increases to \[4\frac{1}{2}\]metres at other end. Find the volume of water in the swimming pool.

    A)  900 \[metr{{e}^{3}}\]             

    B)  456 \[metr{{e}^{3}}\] 

    C)  942 \[metr{{e}^{3}}\]             

    D)  924 \[metr{{e}^{3}}\]

    Correct Answer: B

    Solution :

    (b): The cross section of swimming pool is like a trapezium, of which parallel sides are \[4\frac{1}{2}\] metres and \[1\frac{1}{2}\]metres and vertical perpendicular is 32 metres \[\therefore \]Area of cross section \[=\frac{1}{2}\times 16\times \left( 4\frac{1}{2}+1\frac{1}{2} \right)=48\]sq. m. \[\therefore \]Volume of water in swimming pool = Area of cross section \[\times \]Length \[=48\times 9.5=456\]cubic metres.


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